Example Find voltage across 2k ohm resistor.
Solution:
Combine 2k and 2k and then
At node (1)
V1/3k +4mA +2mA + (V1-V2) /6k =0
2V1 +24 +12 +V1 – V2 =0
3V1 –V2 = -36-------- Equation 1
At node (2)
V2/4k + V2/12k - 2mA +(V2 –V1)/6k = 0
3V2 +V2– 24 + 2V2 – 2V1 = 0
6V2 – 2V1 = 24-------------- Equation 2
9V2 – 3V1 =36 This come from where ????
-V2 + 3V1 =-36 -------------- Equation 1
8V2 =0
V2 =0
you can see from the circuit on the right side two resistance
are in series i:e 2k and 2k ohm so we will apply voltage divider rule here
V0 = 2/4 x V2
= 2/4 x 0
= 0
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