= p (1st wear seatbelt & 2nd waer SeatBelt) = P (A) AND p(B)
= 43/100 * 43/100 = 0.18 = 18%
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On Fri, Mar 5, 2010 at 1:02 PM, mc090402128 Amna Mahvish <mc090402128@vu.edu.pk> wrote:
Question No: 14 ( Marks: 1 ) - Please choose one
In the United States, 43% of people wear a seat belt while driving. If two people are chosen at random, what is the probability that both of them wear a seat belt?
► 18%
► 20%
► 25%
► None of theseplzz send me the total solution
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